---
title: "A student titrates a \\(50.0 \\text{ mL}\\) sample of \\(0.100 \\text{ M HA(aq)}\\) (\\(K_a = 5.0 \\times 10^{-6}\\) at \\(25^\\circ\\text{C}\\)) with \\(0.100 \\text{ M NaOH(aq)}\\) at \\(25^\\circ\\text{C}\\). What is the value of \\([\\text{H}_3\\text{O}^+]\\) in the mixture when the titration reaches the equivalence point?"
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url: "https://nerd-notes.com/ubq/123798/"
date_modified: "2026-09-28T12:30:20+00:00"
---

# A student titrates a \(50.0 \text{ mL}\) sample of \(0.100 \text{ M HA(aq)}\) (\(K_a = 5.0 \times 10^{-6}\) at \(25^\circ\text{C}\)) with \(0.100 \text{ M NaOH(aq)}\) at \(25^\circ\text{C}\). What is the value of \([\text{H}_3\text{O}^+]\) in the mixture when the titration reaches the equivalence point?

A student titrates a \(50.0 \text{ mL}\) sample of \(0.100 \text{ M HA(aq)}\) (\(K_a = 5.0 \times 10^{-6}\) at \(25^\circ\text{C}\)) with \(0.100 \text{ M NaOH(aq)}\) at \(25^\circ\text{C}\). What is the value of \([\text{H}_3\text{O}^+]\) in the mixture when the titration reaches the equivalence point?

- **A.** \(1.0 \times 10^{-9} \text{ M}\)
- **B.** \(1.0 \times 10^{-5} \text{ M}\)
- **C.** \(5.0 \times 10^{-4} \text{ M}\)
- **D.** \(7.1 \times 10^{-4} \text{ M}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/123798/*