---
title: "At \\(700\\text{ K}\\), the equilibrium constants for two gas-phase reactions are given below:  \\[ 2\\,\\text{NO}_2\\text{(g)} \\rightleftharpoons 2\\,\\text{NO(g)} + \\text{O}_2\\text{(g)} \\quad\\quad K_1 = 3.6 \\times 10^{-2} \\]  \\[ \\text{N}_2\\text{(g)} + \\text{O}_2\\text{(g)} \\rightleftharpoons 2\\,\\text{NO(g)} \\quad\\quad K_2 = 4.0 \\times 10^{-5} \\]  Based on these data, what is the value of the equilibrium constant, \\(K_3\\), at \\(700\\text{ K}\\) for the reaction represented below?  \\[ \\text{NO}_2\\text{(g)} \\rightleftharpoons \\frac{1}{2}\\,\\text{N}_2\\text{(g)} + \\text{O}_2\\text{(g)} \\quad\\quad K_3 = \\,? \\]"
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date_modified: "2026-09-28T12:30:32+00:00"
---

# At \(700\text{ K}\), the equilibrium constants for two gas-phase reactions are given below:

\[ 2\,\text{NO}_2\text{(g)} \rightleftharpoons 2\,\text{NO(g)} + \text{O}_2\text{(g)} \quad\quad K_1 = 3.6 \times 10^{-2} \]

\[ \text{N}_2\text{(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\,\text{NO(g)} \quad\quad K_2 = 4.0 \times 10^{-5} \]

Based on these data, what is the value of the equilibrium constant, \(K_3\), at \(700\text{ K}\) for the reaction represented below?

\[ \text{NO}_2\text{(g)} \rightleftharpoons \frac{1}{2}\,\text{N}_2\text{(g)} + \text{O}_2\text{(g)} \quad\quad K_3 = \,? \]

At \(700\text{ K}\), the equilibrium constants for two gas-phase reactions are given below:

\[ 2\,\text{NO}_2\text{(g)} \rightleftharpoons 2\,\text{NO(g)} + \text{O}_2\text{(g)} \quad\quad K_1 = 3.6 \times 10^{-2} \]

\[ \text{N}_2\text{(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\,\text{NO(g)} \quad\quad K_2 = 4.0 \times 10^{-5} \]

Based on these data, what is the value of the equilibrium constant, \(K_3\), at \(700\text{ K}\) for the reaction represented below?

\[ \text{NO}_2\text{(g)} \rightleftharpoons \frac{1}{2}\,\text{N}_2\text{(g)} + \text{O}_2\text{(g)} \quad\quad K_3 = \,? \]

- **A.** \(1.2 \times 10^{-3}\)
- **B.** \(3.0 \times 10^1\)
- **C.** \(9.0 \times 10^2\)
- **D.** \(8.1 \times 10^5\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/123849/*