---
title: "An airplane with a speed of \\( 97.5 \\, \\text{m/s} \\) is climbing upward at an angle of \\( 50.0^\\circ \\) with respect to the horizontal. When the plane’s altitude is \\( 732 \\, \\text{m} \\), the pilot releases a package."
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url: "https://nerd-notes.com/ubq/19534/"
date_modified: "2024-09-25T02:56:03+00:00"
---

# An airplane with a speed of \( 97.5 \, \text{m/s} \) is climbing upward at an angle of \( 50.0^\circ \) with respect to the horizontal. When the plane’s altitude is \( 732 \, \text{m} \), the pilot releases a package.

An airplane with a speed of \( 97.5 \, \text{m/s} \) is climbing upward at an angle of \( 50.0^\circ \) with respect to the horizontal. When the plane’s altitude is \( 732 \, \text{m} \), the pilot releases a package.

**Part a)** Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth. *(3 points)*

**Part b)** Relative to the ground, determine the angle of the velocity vector of the package just before impact. *(4 points)*


*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/19534/*