---
title: "A construction worker spins a square sheet of metal of mass 0.040 kg with an angular acceleration of 10.0 rad/s2 on a vertical spindle (pin). What are the dimensions of the sheet if the net torque on the sheet is 1.00 N·m? Assume that the moment of inertia of a rectangle is [katex] I = \\frac{1}{12}M(a^2+b^2) [/katex] "
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url: "https://nerd-notes.com/ubq/33974/"
date_modified: "2024-04-24T02:42:06+00:00"
---

# A construction worker spins a square sheet of metal of mass 0.040 kg with an angular acceleration of 10.0 rad/s2 on a vertical spindle (pin). What are the dimensions of the sheet if the net torque on the sheet is 1.00 N·m? Assume that the moment of inertia of a rectangle is [katex] I = \frac{1}{12}M(a^2+b^2) [/katex] 

A construction worker spins a square sheet of metal of mass 0.040 kg with an angular acceleration of 10.0 rad/s2 on a vertical spindle (pin). What are the dimensions of the sheet if the net torque on the sheet is 1.00 N·m? Assume that the moment of inertia of a rectangle is \( I = \frac{1}{12}M(a^2+b^2) \)

- **A.** 3.9 m
- **B.** 5.5 m
- **C.** 7.0 m
- **D.** 8.3 m
- **E.** Impossible to calculate with the given information.

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/33974/*