---
title: "A \\(25 \\, \\text{g}\\) steel ball is attached to the top of a \\(24 \\, \\text{cm}\\)-diameter vertical wheel. Starting from rest, the wheel accelerates at \\(470 \\, \\text{rad/s}^2\\). The ball is released after \\(\\frac{3}{4}\\) of a revolution. How high does it go above the center of the wheel?"
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url: "https://nerd-notes.com/ubq/39066/"
date_modified: "2026-04-11T08:42:04+00:00"
---

# A \(25 \, \text{g}\) steel ball is attached to the top of a \(24 \, \text{cm}\)-diameter vertical wheel. Starting from rest, the wheel accelerates at \(470 \, \text{rad/s}^2\). The ball is released after \(\frac{3}{4}\) of a revolution. How high does it go above the center of the wheel?

A \(25 \, \text{g}\) steel ball is attached to the top of a \(24 \, \text{cm}\)-diameter vertical wheel of negligible mass. Starting from rest, the wheel accelerates at \(470 \, \text{rad/s}^2\). The ball is released after \(\frac{3}{4}\) of a revolution. How high does it go above the center of the wheel?

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/39066/*