---
title: "A bullet (mass: \\(0.05 \\, \\text{kg}\\)) is fired horizontally (\\(v = 200 \\, \\text{m/s}\\)) at a block (mass: \\(1.3 \\, \\text{kg}\\)) initially at rest on a frictionless surface. The block is attached to a spring (\\(k = 2500 \\, \\text{N/m}\\)). The bullet becomes embedded. Calculate:"
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url: "https://nerd-notes.com/ubq/39199/"
date_modified: "2025-03-07T07:22:42+00:00"
---

# A bullet (mass: \(0.05 \, \text{kg}\)) is fired horizontally (\(v = 200 \, \text{m/s}\)) at a block (mass: \(1.3 \, \text{kg}\)) initially at rest on a frictionless surface. The block is attached to a spring (\(k = 2500 \, \text{N/m}\)). The bullet becomes embedded. Calculate:

A bullet (mass: \(0.05 \, \text{kg}\)) is fired horizontally (\(v = 200 \, \text{m/s}\)) at a block (mass: \(1.3 \, \text{kg}\)) initially at rest on a frictionless surface. The block is attached to a spring (\(k = 2500 \, \text{N/m}\)). The bullet becomes embedded. Calculate:

![Diagram](https://nerd-notes.com/wp-content/uploads/2024/06/Screen-Shot-2024-06-06-at-7.12.16-PM.png)

**Part a)** The speed of the block immediately after the impact by the bullet. *(3 points)*

**Part b)** The amplitude of the resulting oscillation of the block *(3 points)*

**Part c)** The frequency of the resulting oscillations. *(3 points)*

**Part d)** The equation of motion of the block (assuming that at \( t = 0 \), \( x = 0 \)). *(3 points)*

**Part e)** The period of the oscillation. *(3 points)*


*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/39199/*