---
title: "A solid sphere \\( I = 0.06 \\, \\text{kg} \\cdot \\text{m}^2 \\) spins freely around an axis through its center at an angular speed of \\( 20 \\, \\text{rad/s} \\). It is desired to bring the sphere to rest by applying a friction force of magnitude \\( 2.0 \\, \\text{N} \\) to the sphere’s outer surface, a distance of \\( 0.30 \\, \\text{m} \\) from the sphere’s center. How much time will it take the sphere to come to rest?"
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url: "https://nerd-notes.com/ubq/39440/"
date_modified: "2025-03-03T07:45:16+00:00"
---

# A solid sphere \( I = 0.06 \, \text{kg} \cdot \text{m}^2 \) spins freely around an axis through its center at an angular speed of \( 20 \, \text{rad/s} \). It is desired to bring the sphere to rest by applying a friction force of magnitude \( 2.0 \, \text{N} \) to the sphere’s outer surface, a distance of \( 0.30 \, \text{m} \) from the sphere’s center. How much time will it take the sphere to come to rest?

A solid sphere \( I = 0.06 \, \text{kg} \cdot \text{m}^2 \) spins freely around an axis through its center at an angular speed of \( 20 \, \text{rad/s} \). It is desired to bring the sphere to rest by applying a friction force of magnitude \( 2.0 \, \text{N} \) to the sphere’s outer surface, a distance of \( 0.30 \, \text{m} \) from the sphere’s center. How much time will it take the sphere to come to rest?

- **A.** 4 s
- **B.** 2 s
- **C.** 0.06 s
- **D.** 0.03 s

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/39440/*