---
title: "A solid plastic cube with uniform density (side length = 0.5 \\, m) of mass 100 \\, kg is placed in a vat of fluid whose density is 1200 \\, \\text{kg/m}^3. What fraction of the cube’s volume floats above the surface of the fluid?"
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date_modified: "2025-03-04T07:37:45+00:00"
---

# A solid plastic cube with uniform density (side length = 0.5 \, m) of mass 100 \, kg is placed in a vat of fluid whose density is 1200 \, \text{kg/m}^3. What fraction of the cube’s volume floats above the surface of the fluid?

A solid plastic cube with uniform density (side length = \(0.5\) \(\text{m}\)) of mass \(100\) \(\text{kg}\) is placed in a vat of fluid whose density is \(1200\) \(\text{kg/m}^3\). What fraction of the cube’s volume floats above the surface of the fluid?

- **A.** \[\frac{1}{9} \]
- **B.** \[ \frac{1}{3} \]
- **C.** \[ \frac{2}{3} \]
- **D.** \[ \frac{4}{5} \]

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/79282/*