---
title: "The moment of inertia of a solid cylinder about its axis is given by \\( 0.5MR^2 \\). If this cylinder rolls without slipping, the ratio of its rotational kinetic energy to its translational kinetic energy is"
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date_modified: "2025-03-13T12:18:11+00:00"
---

# The moment of inertia of a solid cylinder about its axis is given by \( 0.5MR^2 \). If this cylinder rolls without slipping, the ratio of its rotational kinetic energy to its translational kinetic energy is

The moment of inertia of a solid cylinder about its axis is given by \( 0.5MR^2 \). If this cylinder rolls without slipping, the ratio of its rotational kinetic energy to its translational kinetic energy is

- **A.** 3:1
- **B.** 1:2
- **C.** 1:3
- **D.** 2:1
- **E.** 1:1

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/81039/*