---
title: "A constant force of strength \\( 20 \\) \\( \\text{N} \\) acts on an object of mass \\( 3 \\) \\( \\text{kg} \\) as it moves a distance of \\( 4 \\) \\( \\text{m} \\). If this force is applied \\textit{perpendicular} to the \\( 4 \\) \\( \\text{m} \\) displacement, the work done by the force is equal to:"
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url: "https://nerd-notes.com/ubq/81063/"
date_modified: "2025-08-04T22:33:09+00:00"
---

# A constant force of strength \( 20 \) \( \text{N} \) acts on an object of mass \( 3 \) \( \text{kg} \) as it moves a distance of \( 4 \) \( \text{m} \). If this force is applied \textit{perpendicular} to the \( 4 \) \( \text{m} \) displacement, the work done by the force is equal to:

A constant force of strength \( 20 \) \( \text{N} \) acts on an object of mass \( 3 \) \( \text{kg} \) as it moves a distance of \( 4 \) \( \text{m} \). If this force is applied perpendicular to the \( 4 \) \( \text{m} \) displacement, the work done by the force is equal to:

- **A.** \( 0 \) \( \text{J} \)
- **B.** \( 60 \) \( \text{J} \)
- **C.** \( 80 \) \( \text{J} \)
- **D.** \( 600 \) \( \text{J} \)
- **E.** \( 2000 \) \( \text{J} \)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/81063/*