---
title: "A cart begins to move from rest on a horizontal track. The acceleration of the cart as a function of time is shown in the graph: from \\( 0 \\) to \\( 1.0 \\) \\( \\text{s} \\) the acceleration is \\( 2.0 \\) \\( \\text{m/s}^2 \\), and from \\( 1.0 \\) to \\( 2.0 \\) \\( \\text{s} \\) the acceleration is \\( 0 \\). Which of the following correctly indicates the magnitude of the average velocity of the cart during the interval shown and provides a valid explanation?"
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url: "https://nerd-notes.com/ubq/88558/"
date_modified: "2025-04-27T07:36:57+00:00"
---

# A cart begins to move from rest on a horizontal track. The acceleration of the cart as a function of time is shown in the graph: from \( 0 \) to \( 1.0 \) \( \text{s} \) the acceleration is \( 2.0 \) \( \text{m/s}^2 \), and from \( 1.0 \) to \( 2.0 \) \( \text{s} \) the acceleration is \( 0 \). Which of the following correctly indicates the magnitude of the average velocity of the cart during the interval shown and provides a valid explanation?

A cart begins to move from rest on a horizontal track. Which of the following correctly indicates the magnitude of the average velocity of the cart during the interval shown and provides a valid explanation?

Hint: when solving this, its consider that the area of the acceleration vs time graph tells you the change in velocity.

![Diagram](https://nerd-notes.com/wp-content/uploads/2025/04/accelvstine948ubq-1.png)

- **A.** Less than \( 2 \) \( \text{m/s} \) because the cart has a velocity of \( 2 \) \( \text{m/s} \) for the first half of the interval and zero velocity for the second half.
- **B.** Less than \( 2 \) \( \text{m/s} \) because the cart is traveling at a speed of \( 2 \) \( \text{m/s} \) or less during the time interval.
- **C.** Equal to \( 2 \) \( \text{m/s} \) because the cart is initially at rest and then moves at a constant speed of \( 2 \) \( \text{m/s} \) during the second half of the interval.
- **D.** Equal to \( 2 \) \( \text{m/s} \) because the cart has an average acceleration of \( 1 \) \( \text{m/s}^2 \) over an interval of \( 2 \) \( \text{s} \).

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/88558/*