---
title: "A miniature, solid globe with mass \\( 0.25 \\) \\( \\text{kg} \\) and radius \\( 0.10 \\) \\( \\text{m} \\) is spinning in place about a vertical axis with the equator horizontal, as shown. A point on the globe’s equator, represented by the dot in the figure, has a linear speed of \\( 4.0 \\) \\( \\text{m/s} \\). The rotational inertia of a solid sphere of mass \\( m \\) and radius \\( r \\) is \\( \\tfrac{2}{5}mr^{2} \\). The rotational kinetic energy of the globe is most nearly"
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url: "https://nerd-notes.com/ubq/90609/"
date_modified: "2026-03-17T00:51:38+00:00"
---

# A miniature, solid globe with mass \( 0.25 \) \( \text{kg} \) and radius \( 0.10 \) \( \text{m} \) is spinning in place about a vertical axis with the equator horizontal, as shown. A point on the globe’s equator, represented by the dot in the figure, has a linear speed of \( 4.0 \) \( \text{m/s} \). The rotational inertia of a solid sphere of mass \( m \) and radius \( r \) is \( \tfrac{2}{5}mr^{2} \). The rotational kinetic energy of the globe is most nearly

A miniature, solid globe with mass \( 0.25 \) \( \text{kg} \) and radius \( 0.10 \) \( \text{m} \) is spinning in place about a vertical axis with the equator horizontal, as shown. A point on the globe’s equator, represented by the dot in the figure, has a linear speed of \( 4.0 \) \( \text{m/s} \). The rotational inertia of a solid sphere of mass \( m \) and radius \( r \) is \( \tfrac{2}{5}mr^{2} \). The rotational kinetic energy of the globe is most nearly

- **A.** \[ 0.8 \, \text{J} \]
- **B.** \[ 2.0 \, \text{J} \]
- **C.** \[ 4.0 \, \text{J} \]
- **D.** \[ 200 \, \text{J} \]

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/90609/*
