---
title: "A \\( 10.0 \\) \\( \\text{g} \\) bullet is fired into a stationary block of wood having mass (\\( m = 5.00 \\) \\( \\text{kg} \\)). The bullet embeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is \\( 0.600 \\) \\( \\text{m/s} \\). What was the original speed of the bullet?"
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url: "https://nerd-notes.com/ubq/90862/"
date_modified: "2026-08-18T02:39:49+00:00"
---

# A \( 10.0 \) \( \text{g} \) bullet is fired into a stationary block of wood having mass (\( m = 5.00 \) \( \text{kg} \)). The bullet embeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is \( 0.600 \) \( \text{m/s} \). What was the original speed of the bullet?

A \( 10.0 \) \( \text{g} \) bullet is fired into a stationary block of wood having mass (\( m = 5.00 \) \( \text{kg} \)). The bullet embeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is \( 0.600 \) \( \text{m/s} \). What was the original speed of the bullet?

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/90862/*