---
title: "A ball is shot from the top of a building with an initial velocity of \\( 18 \\) \\( \\text{m/s} \\) at an angle \\( \\theta = 42^\\circ \\) above the horizontal."
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/91363/"
date_modified: "2025-05-08T03:03:35+00:00"
---

# A ball is shot from the top of a building with an initial velocity of \( 18 \) \( \text{m/s} \) at an angle \( \theta = 42^\circ \) above the horizontal.

A ball is shot from the top of a building with an initial velocity of \( 18 \) \( \text{m/s} \) at an angle \( \theta = 42^\circ \) above the horizontal.

**Part a)** What are the horizontal and vertical components of the initial velocity? *(3 points)*

**Part b)** If a nearby building is the same height and \( 55 \) \( \text{m} \) away, how far below the top of the building will the ball strike the nearby building? *(3 points)*


*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/91363/*