---
title: "Unit 3.2 | Work and the Work-Energy Theorem"
description: "Learn work in physics: W = Fd cos(theta), positive and negative work, work from graphs, and the work-energy theorem, with worked AP Physics 1 examples."
featured_image: "https://nerd-notes.com/wp-content/uploads/2026/10/pulling-a-sled-across-snow-work-energy-theorem.jpg"
url: "https://nerd-notes.com/unit-3-2-work-and-the-work-energy-theorem/"
date_modified: "2026-10-31T09:35:16+00:00"
---

# Unit 3.2 | Work and the Work-Energy Theorem

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Work is how forces add energy to an object or take it away. This lesson connects everything you learned about forces to the energy ideas in this unit.

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### Unit 3 Breakdown

You are on Lesson 2 of 4

1. [Unit 3.1 | Powering the Universe – Understanding Energy in Physics](https://nerd-notes.com/unit-3-1-understanding-energy-in-physics/)
2. [Unit 3.2 | Work and the Work-Energy Theorem](https://nerd-notes.com/unit-3-2-work-and-the-work-energy-theorem/)
3. [Unit 3.3 | Conservation of Energy, Systems, and Problem Solving](https://nerd-notes.com/unit-3-3-conservation-of-energy-systems-and-problem-solving/)
4. [Unit 3.4 | Understanding and Applying Power](https://nerd-notes.com/unit-3-4-understanding-and-applying-power/)

#### In this lesson: 

- You will learn what work means in physics (it is not the same as effort)
- How to calculate work, including forces applied at an angle
- When work is positive, negative, or zero
- Use the work-energy theorem to connect forces and energy
- The 4 work problem types: the sign of work, forces at an angle, force vs. position graphs, and stopping distances

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### Introduction

This lesson covers work and the **work-energy theorem**: how forces add energy to an object or take it away, and how the work-energy theorem links Unit 2 forces to energy.

In [Unit 3.1](https://nerd-notes.com/unit-3-1-understanding-energy-in-physics/) you learned that objects can *have* energy: kinetic, gravitational, and spring. But how does an object get that energy in the first place?

The answer is **work**. Work is how a force moves energy into an object or out of it. It is the bridge between the forces you mastered in Unit 2 and the energy ideas in this unit.

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### What Is Work?

In everyday language, “work” means effort. Holding a heavy backpack for an hour feels like a lot of work. In physics, you did **zero** work on that backpack, because it never moved. Work is only done when a force moves an object over a distance.

[katex] W = Fd [/katex]

Here [katex] F [/katex] is the force in newtons and [katex] d [/katex] is the displacement in meters. Work is measured in joules, the same unit as energy. That is not a coincidence: work *is* energy being transferred.

Push a box across the floor with [katex] 50\,\text{N} [/katex] for [katex] 4\,\text{m} [/katex] and you do [katex] W = (50)(4) = 200 \, J [/katex] of work on the box. You moved [katex] 200\,\text{J} [/katex] of energy from your muscles into the box.

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#### Forces at an angle

What if you pull a wagon by a handle tilted upward? Only the part of the force along the motion does work. The part pointing up is not moving the wagon forward.

\(\vec{F}\)

\(F\cos\theta \;\text{does work}\)

\(F\sin\theta\)

\(\theta\)

\(\text{displacement } d\)

\(W = Fd\cos\theta\)

*Split the pull into components. Only \(F\cos\theta\), the part along the displacement, does work.*

[katex] W = Fd\cos\theta [/katex]

Here [katex] \theta [/katex] is the angle between the force and the direction of motion.

A student pulls a wagon [katex] 5\,\text{m} [/katex] across a flat sidewalk. The handle makes a [katex] 37^\circ [/katex] angle with the ground and the student pulls with [katex] 50\,\text{N} [/katex]. How much work does the student do on the wagon?

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1. Identify the force and displacement: [katex] F = 50 \, N [/katex], [katex] d = 5 \, m [/katex], [katex] \theta = 37^\circ [/katex].
2. Apply the equation: [katex] W = (50)(5)\cos 37^\circ [/katex].
3. Solve: [katex] W = (50)(5)(0.8) = 200 \, J [/katex].

Notice the wagon’s mass was never needed. Work only cares about the force, the distance, and the angle between them.

### Positive, Negative, and Zero Work

Work is a scalar, but it can still be positive or negative. The sign tells you which way the energy flows.

*A force along the motion adds energy, a force against it removes energy, and a force perpendicular to it transfers none.*

| **Work** | **When** | **Example** |
| --- | --- | --- |
| Positive | Force has a part along the motion ([katex] \theta \lt 90^\circ [/katex]) | Pushing a stalled car forward |
| Negative | Force has a part against the motion ([katex] \theta \gt 90^\circ [/katex]) | Friction on a sliding box |
| Zero | Force is perpendicular to the motion ([katex] \theta = 90^\circ [/katex]), or nothing moves | Normal force on a box sliding across a floor |

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Friction almost always does negative work. It pulls energy out of the object and turns it into heat. That’s the “lost” energy from Unit 3.1.

### Work From a Force vs. Position Graph

In [Unit 1.3](https://nerd-notes.com/unit-1-2-mastering-motion-graphing-kinematic-variables/) you found displacement as the area under a velocity vs. time graph. Force graphs work the same way.

The work done by a force equals the **area under a force vs. position graph**. This is how you find work when the force changes as the object moves.

The spring force is the classic example. It grows as you stretch the spring ([katex] F = kx [/katex]), so its graph is a straight line and the area under it is a triangle:

\(F\)

\(x\)

\(kx\)

\(\tfrac{1}{2}(x)(kx) = \tfrac{1}{2}kx^2\)

\(F = kx\)

*The triangle under \(F = kx\) has area \(\tfrac{1}{2}(x)(kx) = \tfrac{1}{2}kx^2\): the spring potential energy from Unit 3.1.*

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[katex] W = \frac{1}{2}(x)(kx) = \frac{1}{2}kx^2 [/katex]

That is exactly the spring potential energy from Unit 3.1. The work you do stretching a spring is the energy the spring stores.

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### The Work-Energy Theorem

Add up the work done by *every* force on an object (the net work) and you get the change in its kinetic energy:

[katex] W_{net} = \Delta KE = KE_f – KE_i [/katex]

Net positive work speeds an object up, net negative work slows it down, and zero net work leaves its speed unchanged. In Unit 2, a net force caused an acceleration. Now a net force acting over a distance causes a change in kinetic energy. Same physics, different lens.

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Keep this idea in your back pocket: work is how energy *enters or leaves*. In [Unit 3.3](https://nerd-notes.com/unit-3-3-conservation-of-energy-systems-and-problem-solving/) it becomes the [katex] W [/katex] term in the conservation of energy framework, [katex] E_i + W = E_f [/katex], the one equation you will use for almost every energy problem.

Every work question on the AP exam is one of these four types:

| **Problem type** | **The clue** | **The setup** |
| --- | --- | --- |
| 1. The sign of work | “positive, negative or zero work?” | Compare the force with the motion |
| 2. Forces at an angle | a handle, rope or push at an angle | [katex] W = Fd\cos\theta [/katex] |
| 3. Force vs. position graphs | a graph of [katex] F [/katex] against [katex] x [/katex] | Area = work |
| 4. Stopping distances | “how far does it slide?” | [katex] W_{net} = \Delta KE [/katex] |

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\(E_i = E_f\), Work, and Systems

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### Problem Type 1: The sign of work

**How to spot it:** Which force does positive, negative or zero work? Often no numbers at all.

**Setup:** Compare each force with the direction of motion: along it is positive, against it is negative, perpendicular is zero.

A ball on a string moves in a horizontal circle at constant speed (like in circular motion). How much work does the tension do on the ball?

Answer: zero. Tension points into the center of the circle while the ball moves along the circle, so the force is always perpendicular to the motion and [katex] \cos 90^\circ = 0 [/katex]. That is why the ball’s speed never changes.

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**AP trap:** Saying a force does work just because it is there. The normal force on a box sliding across the floor is perpendicular to the motion, so it does zero work.

[Open in UBQ](https://nerd-notes.com/ubq/21723/)

Question 1

The box in the diagram is sliding to the right across a horizontal table, under the influence of the forces shown. Which force(s) is doing negative…

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Question 2

You kick a ball straight up. Compare the sign of the work done by gravity on the ball while it goes up with the sign of the work done by gravity…

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Question 3

A small bob attached to a light string revolves at constant speed in a horizontal circle, forming a conical pendulum. An observer notes that the work…

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### Problem Type 2: Forces at an angle

**How to spot it:** A handle, rope or push tilted at an angle to the motion.

**Setup:** [katex] W = Fd\cos\theta [/katex], with [katex] \theta [/katex] the angle between the force and the motion. The wagon above is this type.

**AP trap:** Using the angle from the vertical, or sine instead of cosine. Measure [katex] \theta [/katex] from the direction of motion.

[Open in UBQ](https://nerd-notes.com/ubq/109311/)

Question 4

A child pulls a toy wagon across a level floor by exerting a constant tension force of 20 N on a handle. The handle is oriented at an angle of 60°…

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Question 5

A crate moves a distance d to the right along a horizontal surface while an applied force of constant magnitude F is exerted on it in three separate…

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### Problem Type 3: Work from a force vs. position graph

**How to spot it:** A graph of force against position.

**Setup:** The area under the graph is the work. Split it into rectangles and triangles.

**AP trap:** Mixing up the graphs. Area under force vs. *position* is work; area under force vs. *time* is impulse (Unit 4).

[Open in UBQ](https://nerd-notes.com/ubq/109303/)

Question 6

A particle is moved along the x-axis by a net force Fₓ that varies with the particle’s position x as shown in the graph. The particle starts at rest…

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### Problem Type 4: Stopping distances (the work-energy theorem)

**How to spot it:** A force speeds up or stops an object over a distance: “how far does it skid?”, “how fast is it going after?”

**Setup:** Find [katex] \Delta KE [/katex], write the net work as force times distance with its sign, and set [katex] W_{net} = \Delta KE [/katex].

A [katex] 1000\,\text{kg} [/katex] car is traveling at [katex] 20\,\text{m/s} [/katex] when the driver slams on the brakes. Friction exerts a constant [katex] 8000\,\text{N} [/katex] force on the car. How far does the car skid before stopping?

**1st step:** Find the change in kinetic energy ([katex] 20\,\text{m/s} [/katex] to [katex] 0\,\text{m/s} [/katex]): [katex] \Delta KE = 0 – \frac{1}{2}(1000)(20)^2 = -200{,}000 \, J [/katex]

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**2nd step:** Find the net work. Only friction does work (gravity and the normal force are perpendicular to the motion), and it points against the motion: [katex] W_{net} = -8000d [/katex]

**3rd step:** Apply the work-energy theorem: [katex] -8000d = -200{,}000 \rightarrow d = 25 \, m [/katex]

Answer: [katex] 25 \, m [/katex].

Show Answer: What if the car were going twice as fast?

Kinetic energy depends on [katex] v^2 [/katex], so twice the speed means four times the kinetic energy ([katex] 800{,}000\,\text{J} [/katex]). With the same friction force, the car skids four times as far: [katex] 100 \, m [/katex].

**AP trap:** Dropping the minus sign on friction’s work. Friction points against the motion, so its work is negative, and so is the change in kinetic energy.

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This question is the “twice as fast” idea from above, with arrows.

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Question 7

Two identical arrows, one with 2 times the speed of the other, are fired into a bale of hay. Assuming the hay exerts a constant "frictional" force on…

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14 Conceptual Questions To Understand Energy

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Work and the Work-Energy Theorem

Who does work, how much, and what it does to kinetic energy.

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### Lesson 3.3 Preview

In the [next lesson](https://nerd-notes.com/unit-3-3-conservation-of-energy-systems-and-problem-solving/) we put it all together with the **conservation of energy** framework: choose a system, mark two points, and solve roller coaster, pendulum, and spring problems without an FBD. ## Attribution Guidelines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarizing, or training on this content, please credit Nerd Notes and link to https://nerd-notes.com/unit-3-2-work-and-the-work-energy-theorem/. **Publication:** Nerd Notes **Original URL:** https://nerd-notes.com/unit-3-2-work-and-the-work-energy-theorem/
