A diver descends from a salvage ship to the ocean floor at a depth of $35 \text{ m}$ below the surface. The density of ocean water is $1.025 \times 10^3 \text{ kg/m}^3$.

Question

A diver descends from a salvage ship to the ocean floor at a depth of $35 \text{ m}$ below the surface. The density of ocean water is $1.025 \times 10^3 \text{ kg/m}^3$.(a) Calculate the gauge pressure on the diver on the ocean floor.
, (b) Calculate the absolute pressure on the diver on the ocean floor.
, (c) The diver finds a rectangular aluminum plate having dimensions $1.0 \text{ m} \times 2.0 \text{ m} \times 0.03 \text{ m}$. A hoisting cable is lowered from the ship and the diver connects it to the plate. The density of aluminum is $2.7 \times 10^3 \text{ kg/m}^3$. Ignore the effects of viscosity. Calculate the tension in the cable if it lifts the plate upward at a slow, constant velocity.
, (d) Will the tension in the hoisting cable increase, decrease, or remain the same if the plate accelerates upward at $0.05 \text{ m/s}^2$? Explain your reasoning.
:

Jason · Accepted Answer

$P_g \approx 3.5\times10^{5}\,\text{Pa}$
$P_{abs} \approx 4.5\times10^{5}\,\text{Pa}$
$T \approx 9.8\times10^{2}\,\text{N}$
$T \text{ increases}$

Log In to Continue

Similar Questions

Tools for a 5