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| Step | Formula / Calculation | Reasoning |
|---|---|---|
| 1 | [katex]\text{Total initial speed} = \sqrt{v_{\text{initial}}^2 + v_{\text{vertical initial}}^2}[/katex] | Calculating the total initial speed of the fish combining its horizontal and vertical velocities. |
| 2 | [katex]\text{Total initial speed} = \sqrt{6.0^2 + 0^2} = 6.0 , \text{m/s}[/katex] | Initial vertical velocity is zero as the fish is dropped, not thrown downwards. |
| 3 | [katex]v_{\text{vertical double}} = \sqrt{\text{double speed}^2 – v_{\text{initial}}^2}[/katex] | Calculating the vertical component of velocity when the total speed doubles. |
| 4 | [katex]\text{Double speed} = 2 \times \text{total initial speed} = 12.0 , \text{m/s}[/katex] | Determining the speed value that is double the initial speed. |
| 5 | [katex]v_{\text{vertical double}} = \sqrt{12.0^2 – 6.0^2}[/katex] | Finding the vertical component when total speed is 12.0 m/s. |
| 6 | [katex]t_{\text{double}} = \frac{v_{\text{vertical double}} – v_{\text{vertical initial}}}{g}[/katex] | Time calculation for the speed to double using the kinematic equation. |
| 7 | [katex]t_{\text{double}} \approx 1.06[/katex] s | Evaluating the time for the fish’s speed to double. |
| 8 | [katex]v_{\text{vertical quadruple}} = \sqrt{\text{quadruple speed}^2 – v_{\text{initial}}^2}[/katex] | Calculating the vertical component of velocity when the total speed quadruples. |
| 9 | [katex]\text{Quadruple speed} = 2 \times \text{double speed} = 24.0 , \text{m/s}[/katex] | Determining the speed value that is double the double speed. |
| 10 | [katex]v_{\text{vertical quadruple}} = \sqrt{24.0^2 – 6.0^2}[/katex] | Finding the vertical component when total speed is 24.0 m/s. |
| 11 | [katex]t_{\text{quadruple}} = \frac{v_{\text{vertical quadruple}} – v_{\text{vertical initial}}}{g}[/katex] | Time calculation for the speed to quadruple. |
| 12 | [katex]t_{\text{quadruple}} \approx 2.37[/katex] s | Evaluating the time for the fish’s speed to quadruple. |
| 13 | [katex]\text{Additional time} = t_{\text{quadruple}} – t_{\text{double}}[/katex] | Calculating the additional time required for the fish’s speed to double again. |
| 14 | [katex]\text{Additional time} \approx 1.31[/katex] s | Evaluating the additional time needed for the fish’s speed to double again from the double speed. |
The time for the fish’s speed to double is approximately 1.06 seconds. The additional time required for the fish’s speed to double again (from double to quadruple the initial speed) is approximately 1.31 seconds.
Just ask: "Help me solve this problem."
A rock is thrown from the top of a \( 15 \) \( \text{m} \) building at an unknown angle and speed. It hits a target on the ground \( 35 \) \( \text{m} \) away horizontally \( 3 \) \( \text{s} \) after launch. What was the rock’s launch angle?
A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of \( 70 \, \text{cm} \) as she throws. She releases the \( 600 \, \text{g} \) javelin \( 2.0 \, \text{m} \) above the ground traveling at an angle of \( 30^\circ \) above the horizontal. In this throw, the javelin hits the ground \( 54 \, \text{m} \) away. Find the following:
A block of mass M1 travels horizontally with a constant speed v0 on a plateau of height H until it comes to a cliff. A toboggan of mass M2 is positioned on level ground below the cliff. The center of the toboggan is a distance D from the base of the cliff.
A drinking fountain projects water at an initial angle of \( 50^ \circ \) above the horizontal, and the water reaches a maximum height of \( 0.150 \) \( \text{m} \) above the point of exit. Assume air resistance is negligible.
A plane, 220 meters high, is dropping a supply crate to an island below. It is traveling with a horizontal velocity of 150 m/s. At what horizontal distance must the plane drop the supply crate for it to land on the island? Use [katex] g = 9.81 \, m/s^2[/katex].
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| Kinematics | Forces |
|---|---|
| \(\Delta x = v_i t + \frac{1}{2} at^2\) | \(F = ma\) |
| \(v = v_i + at\) | \(F_g = \frac{G m_1 m_2}{r^2}\) |
| \(v^2 = v_i^2 + 2a \Delta x\) | \(f = \mu N\) |
| \(\Delta x = \frac{v_i + v}{2} t\) | \(F_s =-kx\) |
| \(v^2 = v_f^2 \,-\, 2a \Delta x\) |
| Circular Motion | Energy |
|---|---|
| \(F_c = \frac{mv^2}{r}\) | \(KE = \frac{1}{2} mv^2\) |
| \(a_c = \frac{v^2}{r}\) | \(PE = mgh\) |
| \(T = 2\pi \sqrt{\frac{r}{g}}\) | \(KE_i + PE_i = KE_f + PE_f\) |
| \(W = Fd \cos\theta\) |
| Momentum | Torque and Rotations |
|---|---|
| \(p = mv\) | \(\tau = r \cdot F \cdot \sin(\theta)\) |
| \(J = \Delta p\) | \(I = \sum mr^2\) |
| \(p_i = p_f\) | \(L = I \cdot \omega\) |
| Simple Harmonic Motion | Fluids |
|---|---|
| \(F = -kx\) | \(P = \frac{F}{A}\) |
| \(T = 2\pi \sqrt{\frac{l}{g}}\) | \(P_{\text{total}} = P_{\text{atm}} + \rho gh\) |
| \(T = 2\pi \sqrt{\frac{m}{k}}\) | \(Q = Av\) |
| \(x(t) = A \cos(\omega t + \phi)\) | \(F_b = \rho V g\) |
| \(a = -\omega^2 x\) | \(A_1v_1 = A_2v_2\) |
| Constant | Description |
|---|---|
| [katex]g[/katex] | Acceleration due to gravity, typically [katex]9.8 , \text{m/s}^2[/katex] on Earth’s surface |
| [katex]G[/katex] | Universal Gravitational Constant, [katex]6.674 \times 10^{-11} , \text{N} \cdot \text{m}^2/\text{kg}^2[/katex] |
| [katex]\mu_k[/katex] and [katex]\mu_s[/katex] | Coefficients of kinetic ([katex]\mu_k[/katex]) and static ([katex]\mu_s[/katex]) friction, dimensionless. Static friction ([katex]\mu_s[/katex]) is usually greater than kinetic friction ([katex]\mu_k[/katex]) as it resists the start of motion. |
| [katex]k[/katex] | Spring constant, in [katex]\text{N/m}[/katex] |
| [katex] M_E = 5.972 \times 10^{24} , \text{kg} [/katex] | Mass of the Earth |
| [katex] M_M = 7.348 \times 10^{22} , \text{kg} [/katex] | Mass of the Moon |
| [katex] M_M = 1.989 \times 10^{30} , \text{kg} [/katex] | Mass of the Sun |
| Variable | SI Unit |
|---|---|
| [katex]s[/katex] (Displacement) | [katex]\text{meters (m)}[/katex] |
| [katex]v[/katex] (Velocity) | [katex]\text{meters per second (m/s)}[/katex] |
| [katex]a[/katex] (Acceleration) | [katex]\text{meters per second squared (m/s}^2\text{)}[/katex] |
| [katex]t[/katex] (Time) | [katex]\text{seconds (s)}[/katex] |
| [katex]m[/katex] (Mass) | [katex]\text{kilograms (kg)}[/katex] |
| Variable | Derived SI Unit |
|---|---|
| [katex]F[/katex] (Force) | [katex]\text{newtons (N)}[/katex] |
| [katex]E[/katex], [katex]PE[/katex], [katex]KE[/katex] (Energy, Potential Energy, Kinetic Energy) | [katex]\text{joules (J)}[/katex] |
| [katex]P[/katex] (Power) | [katex]\text{watts (W)}[/katex] |
| [katex]p[/katex] (Momentum) | [katex]\text{kilogram meters per second (kgm/s)}[/katex] |
| [katex]\omega[/katex] (Angular Velocity) | [katex]\text{radians per second (rad/s)}[/katex] |
| [katex]\tau[/katex] (Torque) | [katex]\text{newton meters (Nm)}[/katex] |
| [katex]I[/katex] (Moment of Inertia) | [katex]\text{kilogram meter squared (kgm}^2\text{)}[/katex] |
| [katex]f[/katex] (Frequency) | [katex]\text{hertz (Hz)}[/katex] |
General Metric Conversion Chart
Example of using unit analysis: Convert 5 kilometers to millimeters.
Start with the given measurement: [katex]\text{5 km}[/katex]
Use the conversion factors for kilometers to meters and meters to millimeters: [katex]\text{5 km} \times \frac{10^3 \, \text{m}}{1 \, \text{km}} \times \frac{10^3 \, \text{mm}}{1 \, \text{m}}[/katex]
Perform the multiplication: [katex]\text{5 km} \times \frac{10^3 \, \text{m}}{1 \, \text{km}} \times \frac{10^3 \, \text{mm}}{1 \, \text{m}} = 5 \times 10^3 \times 10^3 \, \text{mm}[/katex]
Simplify to get the final answer: [katex]\boxed{5 \times 10^6 \, \text{mm}}[/katex]
Prefix | Symbol | Power of Ten | Equivalent |
|---|---|---|---|
Pico- | p | [katex]10^{-12}[/katex] | |
Nano- | n | [katex]10^{-9}[/katex] | |
Micro- | µ | [katex]10^{-6}[/katex] | |
Milli- | m | [katex]10^{-3}[/katex] | |
Centi- | c | [katex]10^{-2}[/katex] | |
Deci- | d | [katex]10^{-1}[/katex] | |
(Base unit) | – | [katex]10^{0}[/katex] | |
Deca- or Deka- | da | [katex]10^{1}[/katex] | |
Hecto- | h | [katex]10^{2}[/katex] | |
Kilo- | k | [katex]10^{3}[/katex] | |
Mega- | M | [katex]10^{6}[/katex] | |
Giga- | G | [katex]10^{9}[/katex] | |
Tera- | T | [katex]10^{12}[/katex] |
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