A block of mass \(M_1\) travels horizontally with a constant speed \(v_0\) on a plateau of height \(H\) until it comes to a cliff. A toboggan of mass \(M_2\) is positioned on level ground below the cliff. The center of the toboggan is a distance \(D\) from the base of the cliff.(a) Determine \(D\) in terms of \(v_0\), \(H\), and \(g\) so that the block lands in the center of the toboggan. , (b) The block sticks to the toboggan which is free to slide without friction. Determine the resulting velocity of the block and toboggan. :

\(D = v_0 \sqrt{\tfrac{2H}{g}}\) \(v_x = \frac{M_1}{M_1 + M_2} v_0\)

A block of mass \(M_1\) travels horizontally with a constant speed \(v_0\) on a plateau of height \(H\) until it comes to a cliff. A toboggan of mass \(M_2\) is positioned on level ground below the cliff. The center of the toboggan is a distance \(D\) from the base of the cliff. • Nerd Notes

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AP Physics 1

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A block of mass \(M_1\) travels horizontally with a constant speed \(v_0\) on a plateau of height \(H\) until it comes to a cliff. A toboggan of mass \(M_2\) is positioned on level ground below the cliff. The center of the toboggan is a distance \(D\) from the base of the cliff.

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