| Step | Derivation/Formula | Reasoning |
|---|---|---|
| 1 | \[ A_1 = \frac{\pi d_1^2}{4} \quad , \quad A_2 = \frac{\pi d_2^2}{4} \] | Calculate the cross-sectional areas of the pipe at street level and top floor using the area formula for a circle. Here, \(d_1 = 0.05\,m\) and \(d_2 = 0.028\,m\). |
| 2 | \[ A_1 v_i = A_2 v_x \] | Apply the continuity equation for incompressible flow which states that the volumetric flow rate must remain constant. |
| 3 | \[ v_x = \frac{A_1}{A_2} v_i = \left(\frac{d_1}{d_2}\right)^2 v_i \] | Simplify the expression by canceling the common factor \(\frac{\pi}{4}\) in the area formulas, showing that the velocity scales as the square of the diameter ratio. |
| 4 | \[ v_x = \left(\frac{0.05}{0.028}\right)^2 (0.78) \approx 2.48\,m/s \] | Substitute the given values: \(d_1 = 0.05\,m\), \(d_2 = 0.028\,m\), and \(v_i = 0.78\,m/s\). The ratio \(\left(\frac{0.05}{0.028}\right)^2 \) is approximately 3.188; multiplying by 0.78 yields \(v_x \approx 2.48\,m/s\). |
| 5 | \[ \boxed{v_x \approx 2.48\, m/s} \] | This is the final computed flow velocity at the top floor of the building. |
| Step | Derivation/Formula | Reasoning |
|---|---|---|
| 1 | \[ \frac{P_1}{\rho} + \frac{v_i^2}{2} + g y_1 = \frac{P_2}{\rho} + \frac{v_x^2}{2} + g y_2 \] | Write Bernoulli’s equation between the street level (point 1) and the top floor (point 2). Here, \(y_1 = 0\) and \(y_2 = 16\,m\). |
| 2 | \[ \frac{P_2}{\rho} = \frac{P_1}{\rho} + \frac{v_i^2 – v_x^2}{2} – g \Delta y \] | Rearrange the equation to solve for \(P_2\), where \(\Delta y = y_2 – y_1 = 16\,m\). |
| 3 | \[ P_2 = P_1 + \rho \left(\frac{v_i^2 – v_x^2}{2} – g \Delta y \right) \] | Multiply both sides by the density \(\rho\) to isolate \(P_2\). |
| 4 | \[ P_1 = 3.8\,atm = 3.8 \times 101325 \approx 385035\,Pa \] | Convert the gauge pressure at street level from atmospheres to Pascals using \(1\,atm \approx 101325\,Pa\). |
| 5 | \[ \frac{v_i^2 – v_x^2}{2} = \frac{0.78^2 – 2.48^2}{2} \approx \frac{0.6084 – 6.1504}{2} \approx -2.77\, m^2/s^2 \] | Calculate the difference in kinetic energy per unit mass between the two points. |
| 6 | \[ g \Delta y = 9.8 \times 16 \approx 156.8\, m^2/s^2 \] | Compute the gravitational potential energy change per unit mass over a height of \(16\,m\). |
| 7 | \[ \rho \left( \frac{v_i^2 – v_x^2}{2} – g \Delta y \right) \approx 1000 \left(-2.77 – 156.8\right) \approx -159570\,Pa \] | Combine the kinetic and potential terms multiplied by the density \(\rho = 1000\,kg/m^3\) to find the pressure change. |
| 8 | \[ P_2 \approx 385035 – 159570 \approx 225465\,Pa \] | Subtract the pressure drop from the initial gauge pressure to get the gauge pressure at the top floor. |
| 9 | \[ \boxed{P_2 \approx 2.25 \times 10^5\,Pa} \] | This is the final gauge pressure of the water in the pipe on the top floor. |
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A stepped pulley consists of two rigidly connected concentric solid disks that rotate together on a frictionless horizontal axle. The outer disk has radius \(R\) and the inner disk has radius \(r\). The total rotational inertia of the pulley about the axle is \(I\).
A block of mass \(m_1\) hangs from a light string wrapped around the outer disk. A second block of mass \(m_2\) hangs from a light string wrapped around the inner disk. The strings do not slip. They are wrapped such that Block 1 exerts a counterclockwise torque and Block 2 exerts a clockwise torque on the pulley.
The system is released from rest, and Block 1 is observed to accelerate downward.
A student is tasked with designing an experiment to determine the local acceleration due to gravity, \(g\), using a simple pendulum. The student has access to the following equipment:
– A stable ring stand with a clamp
– A spool of lightweight string
– A set of small hooked spheres of various masses
– A meterstick
– A stopwatch
– A protractor
A projectile is launched from level ground with an initial velocity \(v_0\) at an angle \(\theta\) above the horizontal, where \(0^{\circ} < \theta < 90^{\circ}\). The projectile follows a trajectory through the air and eventually returns to the same level ground. Air resistance is negligible. Which of the following graphs best represents the speed \(v\) of the projectile as a function of time \(t\) from the moment of launch until it hits the ground?

An astronaut on a space station uses a Body Mass Measurement Device (BMMD) to determine their mass in microgravity. The device consists of a seat of mass \(m_s\) attached to a spring with an unknown spring constant \(k\). To calibrate the device, the astronaut attaches several calibration blocks of known mass \(m\) to the seat and measures the period of oscillation \(T\) for each mass. To determine the spring constant \(k\) from a linear graph, which of the following quantities should be plotted on the vertical and horizontal axes, and what is the physical significance of the slope of the resulting best-fit line?

Cart A with mass \(m\) is moving with velocity \(v\) to the right on a horizontal, frictionless track toward Cart B with mass \(2m\), which is initially at rest. The carts collide, and during the collision, Cart A exerts a constant average force of magnitude \(F\) on Cart B for a time interval \(\Delta t\).
Which of the following correctly identifies the change in momentum of Cart A, \(\Delta p_A\), and the change in momentum of the two-cart system, \(\Delta p_{sys}\), during this time interval?
| | \(\Delta p_A\) | \(\Delta p_{sys}\) |
|—|—|—|
| (A) | \(-F\Delta t\) | \(0\) |
| (B) | \(+F\Delta t\) | \(0\) |
| (C) | \(-F\Delta t\) | \(-F\Delta t\) |
| (D) | \(-F\Delta t\) | \(+F\Delta t\) |

A block of mass \(m\) is placed on a frictionless horizontal surface and attached to one end of an ideal spring with spring constant \(k\). The other end of the spring is fixed to a wall. The block is pulled to a displacement of magnitude \(A\) from its equilibrium position and released from rest, causing it to oscillate in simple harmonic motion. Which of the following is a correct expression for the speed of the block when it is at a position \(x = \dfrac{A}{2}\)?

Three blocks, labeled \(X\), \(Y\), and \(Z\), have masses \(m\), \(2m\), and \(3m\), respectively. The blocks are placed on a frictionless horizontal surface in the order \(X\)-\(Y\)-\(Z\) and are pushed to the right by a constant horizontal force of magnitude \(F\) applied to block \(X\). In this configuration, the magnitude of the contact force exerted by block \(Y\) on block \(Z\) is \(F_1\). The blocks are then rearranged on the same surface in the order \(X\)-\(Z\)-\(Y\). The same force \(F\) is applied to block \(X\), and the magnitude of the contact force exerted by block \(Z\) on block \(Y\) is \(F_2\). What is the ratio \(\dfrac{F_2}{F_1}\)?

A large, sealed cylindrical tank is filled with an ideal, incompressible fluid of density \(\rho\) to a total height \(H\). The air in the space above the fluid is maintained at a constant gauge pressure of \(P_G = 4\rho g H\). A small hole is opened in the side of the tank at a depth \(d = 0.5H\) below the fluid’s surface, and the fluid exits with speed \(v_1\). If the top of the tank were instead open to the atmosphere and the hole remained at the same depth, the fluid would exit with speed \(v_2\).
What is the ratio \(v_1 / v_2\)?

An incompressible, nonviscous fluid of density \(\rho\) flows through a horizontal pipe. At a wide section of the pipe, denoted as Point 1, the cross-sectional area is \(A_1\), the fluid speed is \(v_1\), and the pressure is \(P_1\). Further downstream, the pipe narrows to a constriction at Point 2 with a cross-sectional area \(A_2\). Which of the following is a correct expression for the fluid pressure \(P_2\) at the constriction?
A rigid, uniform disk is mounted on a low-friction axle and is initially at rest. A motor applies a net torque to the disk that increases at a constant rate, starting from zero at time \(t = 0\). Which of the following graphs best represents the angular acceleration \(\alpha\) of the disk as a function of time \(t\)?
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| Kinematics | Forces |
|---|---|
| \(\Delta x = v_i t + \frac{1}{2} at^2\) | \(F = ma\) |
| \(v = v_i + at\) | \(F_g = \frac{G m_1 m_2}{r^2}\) |
| \(v^2 = v_i^2 + 2a \Delta x\) | \(f = \mu N\) |
| \(\Delta x = \frac{v_i + v}{2} t\) | \(F_s =-kx\) |
| \(v^2 = v_f^2 \,-\, 2a \Delta x\) |
| Circular Motion | Energy |
|---|---|
| \(F_c = \frac{mv^2}{r}\) | \(KE = \frac{1}{2} mv^2\) |
| \(a_c = \frac{v^2}{r}\) | \(PE = mgh\) |
| \(T = 2\pi \sqrt{\frac{r}{g}}\) | \(KE_i + PE_i = KE_f + PE_f\) |
| \(W = Fd \cos\theta\) |
| Momentum | Torque and Rotations |
|---|---|
| \(p = mv\) | \(\tau = r \cdot F \cdot \sin(\theta)\) |
| \(J = \Delta p\) | \(I = \sum mr^2\) |
| \(p_i = p_f\) | \(L = I \cdot \omega\) |
| Simple Harmonic Motion | Fluids |
|---|---|
| \(F = -kx\) | \(P = \frac{F}{A}\) |
| \(T = 2\pi \sqrt{\frac{l}{g}}\) | \(P_{\text{total}} = P_{\text{atm}} + \rho gh\) |
| \(T = 2\pi \sqrt{\frac{m}{k}}\) | \(Q = Av\) |
| \(x(t) = A \cos(\omega t + \phi)\) | \(F_b = \rho V g\) |
| \(a = -\omega^2 x\) | \(A_1v_1 = A_2v_2\) |
| Constant | Description |
|---|---|
| [katex]g[/katex] | Acceleration due to gravity, typically [katex]9.8 , \text{m/s}^2[/katex] on Earth’s surface |
| [katex]G[/katex] | Universal Gravitational Constant, [katex]6.674 \times 10^{-11} , \text{N} \cdot \text{m}^2/\text{kg}^2[/katex] |
| [katex]\mu_k[/katex] and [katex]\mu_s[/katex] | Coefficients of kinetic ([katex]\mu_k[/katex]) and static ([katex]\mu_s[/katex]) friction, dimensionless. Static friction ([katex]\mu_s[/katex]) is usually greater than kinetic friction ([katex]\mu_k[/katex]) as it resists the start of motion. |
| [katex]k[/katex] | Spring constant, in [katex]\text{N/m}[/katex] |
| [katex] M_E = 5.972 \times 10^{24} , \text{kg} [/katex] | Mass of the Earth |
| [katex] M_M = 7.348 \times 10^{22} , \text{kg} [/katex] | Mass of the Moon |
| [katex] M_M = 1.989 \times 10^{30} , \text{kg} [/katex] | Mass of the Sun |
| Variable | SI Unit |
|---|---|
| [katex]s[/katex] (Displacement) | [katex]\text{meters (m)}[/katex] |
| [katex]v[/katex] (Velocity) | [katex]\text{meters per second (m/s)}[/katex] |
| [katex]a[/katex] (Acceleration) | [katex]\text{meters per second squared (m/s}^2\text{)}[/katex] |
| [katex]t[/katex] (Time) | [katex]\text{seconds (s)}[/katex] |
| [katex]m[/katex] (Mass) | [katex]\text{kilograms (kg)}[/katex] |
| Variable | Derived SI Unit |
|---|---|
| [katex]F[/katex] (Force) | [katex]\text{newtons (N)}[/katex] |
| [katex]E[/katex], [katex]PE[/katex], [katex]KE[/katex] (Energy, Potential Energy, Kinetic Energy) | [katex]\text{joules (J)}[/katex] |
| [katex]P[/katex] (Power) | [katex]\text{watts (W)}[/katex] |
| [katex]p[/katex] (Momentum) | [katex]\text{kilogram meters per second (kgm/s)}[/katex] |
| [katex]\omega[/katex] (Angular Velocity) | [katex]\text{radians per second (rad/s)}[/katex] |
| [katex]\tau[/katex] (Torque) | [katex]\text{newton meters (Nm)}[/katex] |
| [katex]I[/katex] (Moment of Inertia) | [katex]\text{kilogram meter squared (kgm}^2\text{)}[/katex] |
| [katex]f[/katex] (Frequency) | [katex]\text{hertz (Hz)}[/katex] |
Metric Prefixes
Example of using unit analysis: Convert 5 kilometers to millimeters.
Start with the given measurement: [katex]\text{5 km}[/katex]
Use the conversion factors for kilometers to meters and meters to millimeters: [katex]\text{5 km} \times \frac{10^3 \, \text{m}}{1 \, \text{km}} \times \frac{10^3 \, \text{mm}}{1 \, \text{m}}[/katex]
Perform the multiplication: [katex]\text{5 km} \times \frac{10^3 \, \text{m}}{1 \, \text{km}} \times \frac{10^3 \, \text{mm}}{1 \, \text{m}} = 5 \times 10^3 \times 10^3 \, \text{mm}[/katex]
Simplify to get the final answer: [katex]\boxed{5 \times 10^6 \, \text{mm}}[/katex]
Prefix | Symbol | Power of Ten | Equivalent |
|---|---|---|---|
Pico- | p | [katex]10^{-12}[/katex] | 0.000000000001 |
Nano- | n | [katex]10^{-9}[/katex] | 0.000000001 |
Micro- | µ | [katex]10^{-6}[/katex] | 0.000001 |
Milli- | m | [katex]10^{-3}[/katex] | 0.001 |
Centi- | c | [katex]10^{-2}[/katex] | 0.01 |
Deci- | d | [katex]10^{-1}[/katex] | 0.1 |
(Base unit) | – | [katex]10^{0}[/katex] | 1 |
Deca- or Deka- | da | [katex]10^{1}[/katex] | 10 |
Hecto- | h | [katex]10^{2}[/katex] | 100 |
Kilo- | k | [katex]10^{3}[/katex] | 1,000 |
Mega- | M | [katex]10^{6}[/katex] | 1,000,000 |
Giga- | G | [katex]10^{9}[/katex] | 1,000,000,000 |
Tera- | T | [katex]10^{12}[/katex] | 1,000,000,000,000 |
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