AP Physics

Unit 1 - Vectors and Kinematics

Intermediate

Conceptual

MCQ

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Projectiles 1 and 2 are launched from level ground at the same time and follow the trajectories shown in the figure. Which one of the projectiles, if either, returns to the ground first, and why?

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Step Derivation/Formula Reasoning
1 t=2v0yg t = \frac{2v_{0y}}{g} The time of flight for each projectile is determined by the vertical component of the initial velocity v0yv_{0y}.
2 Projectile 1: Higher v0yv_{0y} From the trajectory shape, Projectile 1 reaches a higher height indicating a greater initial vertical velocity v0yv_{0y}.
3 Projectile 2: Lower v0yv_{0y} Projectile 2 has a flatter trajectory, suggesting a smaller initial vertical velocity v0yv_{0y}.
4 Time of flight for Projectile 1>Time of flight for Projectile 2 \text{Time of flight for Projectile 1} > \text{Time of flight for Projectile 2} Since the time of flight depends on the initial vertical velocity, and Projectile 1 has a larger v0yv_{0y}, it stays in the air longer.

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