
Projectiles 1 and 2 are launched from level ground at the same time and follow the trajectories shown in the figure. Which one of the projectiles, if either, returns to the ground first, and why?
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Projectiles 1 and 2 are launched from level ground at the same time and follow the trajectories shown in the figure. Which one of the projectiles, if either, returns to the ground first, and why?
Step | Derivation/Formula | Reasoning |
---|---|---|
1 | t=g2v0y | The time of flight for each projectile is determined by the vertical component of the initial velocity v0y. |
2 | Projectile 1: Higher v0y | From the trajectory shape, Projectile 1 reaches a higher height indicating a greater initial vertical velocity v0y. |
3 | Projectile 2: Lower v0y | Projectile 2 has a flatter trajectory, suggesting a smaller initial vertical velocity v0y. |
4 | Time of flight for Projectile 1>Time of flight for Projectile 2 | Since the time of flight depends on the initial vertical velocity, and Projectile 1 has a larger v0y, it stays in the air longer. |
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You kick a soccer ball with an initial velocity directed 53° above the horizontal. The ball lands on a roof 7.2 m high. The wall of the building is 25 m away, and it takes the ball 2.1 seconds to pass directly over the wall.
A person shoots a basketball with a speed of 12m/s at an angle of 35∘ above the horizontal. If the person is 2.4m tall and the hoop is 3.05m above the ground, how far back must the person stand in order to make the shot?
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