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AP Physics C: E&M
13.1 Magnetic Flux
IntermediateMCQConceptual19.8k
A horizontal bar magnet is shown on the left with its North pole labeled N facing right and South pole labeled S facing left. To the right of the bar magnet, a smooth, closed 3D oval surface labeled S is drawn in space. Magnetic field lines emerge from the N pole, curve toward the right, penetrate the left side of surface S (entering the enclosed volume), pass through the interior region, and penetrate the right side of surface S (exiting the volume), continuing in continuous curves back toward the S pole. Two outward-pointing surface normal vector arrows labeled d\vec{A} are shown on surface S: one on the left pointing outward to the left, and one on the right pointing outward to the right. No other text, labels, or axes appear.
A closed surface S situated in the magnetic field of a magnetic dipole.
A closed surface \(S\) is situated in the non-uniform magnetic field produced by a nearby magnetic dipole, as shown. Magnetic field lines pass through various regions of the surface, yet the net magnetic flux \(\Phi_B = \oint_S \vec{B} \cdot d\vec{A}\) through the closed surface is equal to zero. Which of the following statements correctly explains why the net magnetic flux through the closed surface is zero?

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