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AP Chemistry
2.7 VSEPR and Hybridization
2.5 Lewis Diagrams
2.1 Types of Chemical Bonds
IntermediateMCQDrawing RepresentationsConceptual21.2k
Create a grayscale ball-and-stick VSEPR schematic on a blank background. At the center, place exactly one medium filled circle labeled S. Place exactly four smaller open circles, each labeled F: one directly above the central atom, one directly below it, one at the upper right, and one at the lower right. Connect each terminal circle to the central circle with exactly one straight solid line. The upper and lower bonds are axial and collinear. The two right-hand bonds occupy equatorial positions and are separated from each other by 120 degrees. Place exactly one pair of adjacent solid dots directly left of the central atom at the third equatorial position; do not connect the dots to the central atom. Show no bond-dipole arrows and no terminal-atom lone pairs because this is a molecular-domain model. No other particles, labels, text, or annotations appear.
VSEPR molecular-domain model of \(\text{SF}_4\)
A student uses a Lewis diagram and VSEPR theory to construct the molecular-domain model of \(\text{SF}_4\) shown. Each \(\text{SF}\) bond is polar because \(\text{F}\) is more electronegative than \(\text{S}\).

Which prediction about the molecular polarity of \(\text{SF}_4\) is consistent with the model?

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