AP Chemistry
6.6 Introduction to Enthalpy of Reaction
6.4 Heat Capacity and Calorimetry
To model a neutralization step in wastewater treatment, a student mixes the following solutions in a constant-pressure calorimeter.
The maximum temperature of the mixture is \(28.40^\circ\text{C}\). Assume that the volumes are additive, the density of the mixture is \(1.00\text{ g/mL}\), its specific heat capacity is \(4.18\text{ J/(g}\cdot^\circ\text{C)}\), and the calorimeter absorbs negligible heat. The reaction is
\(\text{HNO}_3\text{(aq)}+\text{NaOH(aq)}\rightarrow\text{NaNO}_3\text{(aq)}+\text{H}_2\text{O(l)}\)
What is the magnitude of the experimental enthalpy of neutralization per mole of \(\text{H}_2\text{O(l)}\) formed?
| Solution | Volume | Concentration | Initial temperature |
|---|---|---|---|
| \(\text{HNO}_3\text{(aq)}\) | \(40.0\text{ mL}\) | \(1.50\text{ M}\) | \(21.00^\circ\text{C}\) |
| \(\text{NaOH(aq)}\) | \(50.0\text{ mL}\) | \(1.00\text{ M}\) | \(21.00^\circ\text{C}\) |
The maximum temperature of the mixture is \(28.40^\circ\text{C}\). Assume that the volumes are additive, the density of the mixture is \(1.00\text{ g/mL}\), its specific heat capacity is \(4.18\text{ J/(g}\cdot^\circ\text{C)}\), and the calorimeter absorbs negligible heat. The reaction is
\(\text{HNO}_3\text{(aq)}+\text{NaOH(aq)}\rightarrow\text{NaNO}_3\text{(aq)}+\text{H}_2\text{O(l)}\)
What is the magnitude of the experimental enthalpy of neutralization per mole of \(\text{H}_2\text{O(l)}\) formed?
Similar Questions
Tools for a 5
AP aligned mock tests to help you get a 5.
With grading, adaptive explanations, and more.
Find a Quiz
Find, solve, and grade every AP FRQ ever.
Find an FRQ
Stuck on AP Chemistry? Get unstuck with an AP specialist.1 to 1 tutors who know the exam inside out. Understand weeks of material in a single session.Find a Tutor
Learn AP Physics from scratch, quickly. This is the only course you'll need for the year.
A self-paced course with everything you need to get a 5. Trusted by over 15,000 students and 200+ schools. Learn fast, or we'll refund your purchase, backed by our 100% satisfaction guarantee.
Explore the Course