A thin converging glass lens with refractive index \(n_{\text{glass}} = 1.50\) is initially in air (\(n_{\text{air}} = 1.00\)). An object is placed at a fixed distance \(d_o\) to the left of the lens, forming a sharp, real image at a distance \(d_i\) on a screen to the right of the lens. The entire apparatus is then submerged in water (\(n_{\text{water}} = 1.33\)) while keeping the object distance \(d_o\) constant, where \(d_o\) is greater than the new focal length of the lens in water. Which of the following statements correctly predicts how the new image distance compares to the original image distance \(d_i\), and provides the correct physical justification?