An unstable parent nucleus with mass number \(A = 232\) and atomic number \(Z = 90\) undergoes the four-step decay chain listed below.

I. Alpha decay to form nucleus \(\text{Y}_1\)
II. Beta-minus (\(\beta^-\)) decay of nucleus \(\text{Y}_1\) to form nucleus \(\text{Y}_2\)
III. Beta-minus (\(\beta^-\)) decay of nucleus \(\text{Y}_2\) to form nucleus \(\text{Y}_3\)
IV. Alpha decay of nucleus \(\text{Y}_3\) to form nucleus \(\text{Y}_4\)

Option	Atomic Number of \(\text{Y}_2\)	Mass Number of \(\text{Y}_4\)	Atomic Number of \(\text{Y}_4\)
(A)	87	224	88
(B)	89	228	86
(C)	89	224	88
(D)	91	224	90

Which row in the table correctly identifies the atomic number of intermediate nucleus \(\text{Y}_2\) and the mass number and atomic number of final nucleus \(\text{Y}_4\)?