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AP Physics 1
1.5 Vectors and Motion in Two Dimensions
1.1 Scalars and Vectors in One Dimension
IntermediateMCQMathematical10.9k
A two-dimensional Cartesian coordinate system with the origin at the center. The positive ( x )-axis extends horizontally to the right and is labeled “x” at its arrowhead. The positive ( y )-axis extends vertically upward and is labeled “y” at its arrowhead. A thin line continues the axes past the origin into the negative directions, with arrowheads at both negative ends. nnTwo bold vectors originate from the origin. n1. Vector ( vec{A} ) is drawn into the second quadrant, making an angle of ( 23^{circ} ) to the left of the positive ( y )-axis (equivalently ( 67^{circ} ) above the negative ( x )-axis). Its arrowhead points up-left. Near the arrow is the bold letter “A”; beside the vector, the magnitude “6.3” is printed. An arc between the vector and the positive ( y )-axis is marked with the label “23°.” n2. Vector ( vec{B} ) is drawn into the first quadrant, making an angle of ( 34^{circ} ) above the positive ( x )-axis. Its arrowhead points up-right. Near the arrow is the bold letter “B”; beside the vector, the magnitude “5.7” is printed. An arc between the vector and the positive ( x )-axis is marked with the label “34°.” nnNo other vectors are drawn. All vectors originate exactly at the origin and are drawn to scale relative to one another and to the printed magnitudes.

Vectors \( \vec{A} \) and \( \vec{B} \) originate from the same point on a set of perpendicular \( x \)– and \( y \)-axes as shown in the accompanying figure. Vector \( \vec{A} \) has magnitude \( 6.3 \) and is directed \( 23^{\circ} \) to the left of the positive \( y \)-axis. Vector \( \vec{B} \) has magnitude \( 5.7 \) and is directed \( 34^{\circ} \) above the positive \( x \)-axis. A third vector is defined by \( \vec{C} = \vec{B} – \vec{A} \). What is the magnitude of \( \vec{C} \)?

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