Two identical gas samples containing hydrogen atoms in the excited state \(n = 4\) undergo de-excitation to the ground state \(n = 1\). In Sample 1, all atoms decay via a single direct transition (\(n = 4 \rightarrow n = 1\)). In Sample 2, all atoms decay via a two-step cascade transition (\(n = 4 \rightarrow n = 2 \rightarrow n = 1\)). The photons emitted from each sample strike identical metal plates, each having a work function \(\Phi = 4.0\text{ eV}\). How do the total energy of all photons emitted (\(E_{\text{total}}\)) and the maximum kinetic energy of ejected photoelectrons (\(K_{\text{max}}\)) compare between Sample 1 and Sample 2?