AP Physics 2
13.3 Refraction

\(n_{\text{air}} = 1.00\)) strikes a flat block of glass (
\(n_{\text{glass}} = 1.50\)) at an angle of incidence \(\theta_1 = 30^\circ\), refracting into the glass at an angle \(\theta_2\) measured relative to the normal. The glass block is then submerged in water (
\(n_{\text{water}} = 1.33\)), and a light ray traveling in the water strikes the glass surface at the same angle of incidence \(\theta_1 = 30^\circ\). How does the new angle of refraction in the glass compare to \(\theta_2\), and why?
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