AP Chemistry
3.13 Beer-Lambert Law
A student previously prepared a calibration line for a dissolved dye using clear standards, a clean solvent blank, and clean cuvettes with a path length of \(1.00\text{ cm}\). The resulting calibration relationship is \(A=kc\), where \(k=\varepsilon(1.00\text{ cm})\). The student retains this calibration line and calculates each unknown concentration using \(c_{\text{calc}}=A_{\text{meas}}/k\). The measured absorbance after blanking is described by
\[ A_{\text{meas}}=-\log\left(\dfrac{I}{I_0}\right) \]
where \(I\) is the intensity transmitted through the unknown and \(I_0\) is the intensity transmitted through the blank. Any suspended particles considered are nonabsorbing at the selected wavelength. Which modification would cause \(c_{\text{calc}}\) to be systematically greater than the actual dye concentration for the reason given?
\[ A_{\text{meas}}=-\log\left(\dfrac{I}{I_0}\right) \]
where \(I\) is the intensity transmitted through the unknown and \(I_0\) is the intensity transmitted through the blank. Any suspended particles considered are nonabsorbing at the selected wavelength. Which modification would cause \(c_{\text{calc}}\) to be systematically greater than the actual dye concentration for the reason given?
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