AP Chemistry
7.5 Magnitude of the Equilibrium Constant
7.4 Calculating the Equilibrium Constant
7.3 Reaction Quotient and Equilibrium Constant
A student investigates four different reversible gas-phase reactions at \(500\text{ K}\). Each reaction is allowed to reach chemical equilibrium in a separate rigid container. The balanced chemical equations and the measured equilibrium partial pressures of all species are shown in the table below.
Based on the data in the table, which system is product-favored at \(500\text{ K}\), and why?
| System | Balanced equation | Equilibrium partial pressures (\(\text{atm}\)) |
|---|---|---|
| 1 | \(2\,\text{NO}_2(g) \rightleftharpoons \text{N}_2\text{O}_4(g)\) | \(P_{\text{NO}_2} = 2.0\), \(P_{\text{N}_2\text{O}_4} = 0.40\) |
| 2 | \(\text{CO}(g) + \text{Cl}_2(g) \rightleftharpoons \text{COCl}_2(g)\) | \(P_{\text{CO}} = 0.10\), \(P_{\text{Cl}_2} = 0.10\), \(P_{\text{COCl}_2} = 4.0\) |
| 3 | \(2\,\text{NOCl}(g) \rightleftharpoons 2\,\text{NO}(g) + \text{Cl}_2(g)\) | \(P_{\text{NOCl}} = 1.0\), \(P_{\text{NO}} = 0.20\), \(P_{\text{Cl}_2} = 0.10\) |
| 4 | \(\text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g)\) | \(P_{\text{PCl}_5} = 2.0\), \(P_{\text{PCl}_3} = 0.50\), \(P_{\text{Cl}_2} = 0.50\) |
Based on the data in the table, which system is product-favored at \(500\text{ K}\), and why?
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