A rigid wrench is aligned horizontally along the positive \(x\)-axis with its pivot located at the origin \(x = 0\). A force \(\vec{F}_1\) of magnitude \(30\text{ N}\) is applied vertically upward in the \(+y\)-direction at a distance \(x_1 = 0.20\text{ m}\) from the pivot. A second force \(\vec{F}_2\) of magnitude \(50\text{ N}\) is applied at the end of the wrench at \(x_2 = 0.40\text{ m}\), directed at an angle of \(30^\circ\) below the horizontal. What is the magnitude of the net torque exerted on the wrench about the pivot?