A \( 2 \, \text{kg}\) mass is attached to a spring with spring constant \( k = 100 \, \text{N/m}\) and negligible mass.(a) What will be the period of oscillation of the system if the spring is stretched by i) 0.5 m and ii) 1 m? , (b) How will the period change if the mass is doubled? , (c) Justify your answer to (b) in terms of the spring force on the mass. :

\( T \approx 0.89 \, \text{s} \) for both (i) and (ii). \( T’ \approx 1.26 \, \text{s} \). In other words the period increase by a factor of \( \sqrt2 \). Greater mass leads to reduced acceleration from the same force, increasing time for one complete oscillation.

A 2 kg mass is attached to a spring with spring constant k = 100 N/m and negligible mass. • Nerd Notes

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AP Physics 1

7.2 Frequency and Period of SHM

7.1 Defining Simple Harmonic Motion (SHM)

IntermediateFRQMathematical18.7k

A \( 2 \, \text{kg}\) mass is attached to a spring with spring constant \( k = 100 \, \text{N/m}\) and negligible mass.

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