A \(2\,\text{kg}\) mass is attached to a spring with spring constant \(k = 100\,\text{N/m}\) and negligible mass.(a) What will be the period of oscillation of the system if the spring is stretched by i) \(0.5\,\text{m}\) and ii) \(1\,\text{m}\)? , (b) How will the period change if the mass is doubled? , (c) Justify your answer to (b) in terms of the spring force on the mass. :

\( T \approx 0.89 \, \text{s} \) for both (i) and (ii). \( T’ \approx 1.26 \, \text{s} \). In other words the period increase by a factor of \( \sqrt2 \). Greater mass leads to reduced acceleration from the same force, increasing time for one complete oscillation.

A \(2\,\text{kg}\) mass is attached to a spring with spring constant \(k = 100\,\text{N/m}\) and negligible mass. • Nerd Notes

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AP Physics 1

7.2 Frequency and Period of SHM

7.1 Defining Simple Harmonic Motion (SHM)

IntermediateFRQMathematicalProportional AnalysisConceptual18.7k

A \(2\,\text{kg}\) mass is attached to a spring with spring constant \(k = 100\,\text{N/m}\) and negligible mass.

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