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AP Chemistry
1.7 Periodic Trends
1.6 Photoelectron Spectroscopy
1.5 Atomic Structure and Electron Configuration
AdvancedMCQConceptual16.1k
A grayscale photoelectron spectroscopy diagram consisting of two vertically stacked rectangular panels sharing a common horizontal axis. The horizontal axis is oriented at the bottom with values decreasing logarithmically from left to right, with major tick marks labeled 1000, 100, 10, 1, and 0.1, and an axis title labeled Binding Energy (MJ/mol). The vertical axis on each panel is labeled Relative Number of Electrons. The top panel is labeled Ne and displays three solid black vertical line peaks: peak 1 at 84 MJ/mol with a relative height of 2, peak 2 at 4.7 MJ/mol with a relative height of 2, and peak 3 at 2.1 MJ/mol with a relative height of 6. The bottom panel is labeled Na and displays four solid black vertical line peaks: peak 1 at 104 MJ/mol with a relative height of 2, peak 2 at 6.8 MJ/mol with a relative height of 2, peak 3 at 3.7 MJ/mol with a relative height of 6, and peak 4 at 0.50 MJ/mol with a relative height of 1. No other peaks, curves, gridlines, labels, or annotations appear.
Photoelectron spectra for ground-state \(\text{Ne}\) and \(\text{Na}\) atoms.
Simulated photoelectron spectra (PES) for isolated, ground-state atoms of \(\text{Ne}\) (atomic number \(10\)) and \(\text{Na}\) (atomic number \(11\)) are shown below.

Which of the following best explains why the valence electron peak for \(\text{Na}\) appears at a substantially lower binding energy (\(\approx 0.50 \text{ MJ/mol}\)) than the valence electron peak for \(\text{Ne}\) (\(\approx 2.1 \text{ MJ/mol}\)), despite \(\text{Na}\) having a greater nuclear charge (\(Z = 11\)) than \(\text{Ne}\) (\(Z = 10\))?

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