A $60.0\,\text{cm}$ diameter wheel rotates with a constant angular acceleration of $4.00\,\text{rad/s}^2$. It starts from rest at $t = 0$, and a chalk line drawn to a point, $P$, on the rim of the wheel makes an angle of $57.3^\circ$ with the horizontal at this time. At $t = 2.00\,\text{s}$:

Question

A $60.0\,\text{cm}$ diameter wheel rotates with a constant angular acceleration of $4.00\,\text{rad/s}^2$. It starts from rest at $t = 0$, and a chalk line drawn to a point, $P$, on the rim of the wheel makes an angle of $57.3^\circ$ with the horizontal at this time. At $t = 2.00\,\text{s}$:(a) Find the angular speed of the wheel.
, (b) Find the linear velocity and tangential acceleration of $P$.
, (c) Find the angular position of $P$. In other words, how many degrees did $P$ rotate through.
:

Jason · Accepted Answer

$8.00\,\text{rad/s}$
$2.40\,\text{m/s},\;1.20\,\text{m/s}^2$
$8.00\,\text{rad}\; (458^\circ)$

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