A cylindrical tank of water (height $ H $) is punctured at a height $ h $ above the bottom. How far from the base of the tank will the water stream land (in terms of $ h $ and $ H $)? What must the value of $ h $ be such that the distance at which the stream lands will be equal to $ H $?

Question

A cylindrical tank of water (height $ H $) is punctured at a height $ h $ above the bottom. How far from the base of the tank will the water stream land (in terms of $ h $ and $ H $)? What must the value of $ h $ be such that the distance at which the stream lands will be equal to $ H $?(a) Determine the horizontal distance from the base of the tank at which the water stream will land, expressed in terms of $ h $ and $ H $.
, (b) Determine the value of $ h $ (in terms of $ H $) for which the horizontal distance calculated above is equal to $ H $.
:

Jason · Accepted Answer

$\Delta x = 2\sqrt{h(H-h)}$
$h = \dfrac{H}{2}$

AP Physics 1 With Jason

AP Physics 1

Log In to Continue

Similar Questions

Tools for a 5