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A Venturi meter is a device used for measuring the speed of a fluid within a pipe. The drawing shows a gas flowing at a speed \( v_2 \) through a horizontal section of pipe with a cross-sectional area \( A_2 = 542 \) \( \text{cm}^2 \). The gas has a density of \( 1.35 \) \( \text{kg/m}^3 \). The Venturi meter has a cross-sectional area of \( A_1 = 215 \) \( \text{cm}^2 \) and has been substituted for a section of the larger pipe. The pressure difference between the two sections \( P_2 – P_1 = 145 \) \( \text{Pa} \).

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Water flows from point \( A \) to points \( D \) and \( E \) as shown. Some of the flow parameters are known, as shown in the table. Determine the unknown parameters.
Section Diameter Flow Rate Velocity
\( \text{AB} \) \( 300 \) \( \text{mm} \) ? \( \text{m}^3/\text{s} \) ? \( \text{m/s} \)
\( \text{BC} \) \( 600 \) \( \text{mm} \) ? \( \text{m}^3/\text{s} \) \( 1.2 \) \( \text{m/s} \)
\( \text{CD} \) ? \( \text{mm} \) \( Q_3 = 2Q_4 \) \( \text{m}^3/\text{s} \) \( 1.4 \) \( \text{m/s} \)
\( \text{CE} \) \( 150 \) \( \text{mm} \) \( Q_4 = 0.5Q_3 \) \( \text{m}^3/\text{s} \) ? \( \text{m/s} \)

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The \( 70 \) \( \text{kg} \) student in the figure balances a \( 1200 \) \( \text{kg} \) elephant on a hydraulic lift. Assume that it is filled with oil, which is incompressible and has a density \( \rho = 900 \) \( \text{kg/m}^3 \). What is the diameter of the piston the student is standing on? Assume each piston has a cylindrical shape, i.e., a circular cross-sectional area. Note: The two pistons are at the same height. Also, the diameter of the wider piston is given in the figure to be \( 2.0 \) \( \text{m} \). \textit{Hint: Refer to your notes on Pascal’s Law and hydraulic lifts which says that the forces are related by:} \[ \frac{F_1}{A_1} = \frac{F_2}{A_2} + \rho gh \]

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The experimental diving rig is lowered from rest at the ocean’s surface and reaches a maximum depth of \(80\) \(\text{m}\). Initially it accelerates downward at a rate of \(0.10\) \(\text{m/s}^2\) until it reaches a speed of \(2.0\) \(\text{m/s}\), which then remains constant. During the descent, the pressure inside the bell remains constant at \(1\) atmosphere. The top of the bell has a cross-sectional area \(A = 9.0\) \(\text{m}^2\). The density of seawater is \(1025\) \(\text{kg/m}^3\).

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A beaker weighing \( 2.0 \) \( \text{N} \) is filled with \( 5.0 \times 10^{-3} \) \( \text{m}^3 \) of water. A rubber ball weighing \( 3.0 \) \( \text{N} \) is held entirely underwater by a massless string attached to the bottom of the beaker, as represented in the figure above. The tension in the string is \( 4.0 \) \( \text{N} \). The water fills the beaker to a depth of \( 0.20 \) \( \text{m} \). Water has a density of \( 1000 \) \( \text{kg/m}^3 \). The effects of atmospheric pressure may be neglected. (a) Calculate the weight of the entire apparatus. (b) On the dot below that represents the ball, draw and label the forces (not components) that act on the ball. (c) Calculate the buoyant force exerted on the ball by the water. If you need to draw anything other than what you have shown in part (b) to assist in your solution, use the space below. Do NOT add anything to the figure in part (b). (d) Calculate the pressure due to the liquid (the gauge pressure) at the bottom of the beaker. (e) The string is cut, and the ball rises to the surface and floats. Indicate whether the water level is higher, lower, or the same after equilibrium is reached. ____ Higher ____ Lower ____ The same Justify your answer.

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A diver descends from a salvage ship to the ocean floor at a depth of \(35 \text{ m}\) below the surface. The density of ocean water is \(1.025 \times 10^3 \text{ kg/m}^3\). Calculate the gauge pressure on the diver on the ocean floor. Calculate the absolute pressure on the diver on the ocean floor. The diver finds a rectangular aluminum plate having dimensions \(1.0 \text{ m} \times 2.0 \text{ m} \times 0.03 \text{ m}\). A hoisting cable is lowered from the ship and the diver connects it to the plate. The density of aluminum is \(2.7 \times 10^3 \text{ kg/m}^3\). Ignore the effects of viscosity.

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